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I changed the target URL since the original one was dead: I just looked for a gzip file served from an ftp server like in the original question.

With open(out_file_path, 'w') as outfile: Print('Downloading SEED Database from: '.format(url))Ĭompressed_file = StringIO.StringIO(response.read())ĭecompressed_file = gzip.GzipFile(fileobj=compressed_file) Here's what worked for me (adapted from here): import urllib2 It will extract all the files in the zip if this argument is not provided. In this article you will learn how to download data from the web using Python. ZipFile.extractall ( path None, members None, pwd None) path: location where zip file needs to be extracted if not provided, it will extract the contents in the current directory. The module supports HTTP, HTTPS, FTP and several other protocols. This data can be a file, a website or whatever you want Python to download. I've found this question while searching for methods to download and unzip a gzip file from an URL but I didn't manage to make the accepted answer work in Python 2.7. The urllib2 module can be used to download data from the web (network resource access). Then, we will use the pycurl.Curl () function to create an object and initiate the curl session. First, we have to create a file object for where we wish to download the required file. We can use file handling with this module to download files from the internet. Just gzip.GzipFile(fileobj=handle) and you'll be on your way - in other words, it's not really true that "the Gzip library only accepts filenames as arguments and not handles", you just have to use the fileobj= named argument. Use the pycurl Module to Download Files in Python.